In a geometric series, the second term is 3 and the fifth term is 81. Find the third term.
(please explain clearly and easy to understand if you did that i'll give you a medal)
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OpenStudy (anonymous):
no more circles, lol
OpenStudy (anonymous):
moon, go to school, lol
OpenStudy (anonymous):
hi dipan
OpenStudy (anonymous):
ill go back, one sec
OpenStudy (anonymous):
ar=3
ar^4=81
r=3
a=1
third term ar^2=9
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OpenStudy (anonymous):
ar = 3, how do you know r = 3
OpenStudy (moongazer):
lol you are here again
OpenStudy (anonymous):
i dont think this is right
OpenStudy (anonymous):
ar^4/(ar)=27
r^3=27
r=3...
OpenStudy (anonymous):
do it step by step.....
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OpenStudy (moongazer):
the answer is 9
OpenStudy (anonymous):
oh youre right
OpenStudy (anonymous):
nice :)
OpenStudy (anonymous):
moongazer... i have given the ans....
OpenStudy (anonymous):
give him medal :)
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OpenStudy (moongazer):
i am really confused with geometric and arithmetic series questions do you have tips to be good at it??
OpenStudy (anonymous):
geometric series is given by ar^n. where a is the first term and r is the common ratio. In AP the series is like a+nd. where d is the common difference.
OpenStudy (anonymous):
in geometric when we divide consecutive terms, it is constant
hence the term ratio
OpenStudy (anonymous):
in arithmetic when we subtract terms we get a constant difference
OpenStudy (moongazer):
i already know that geometric series common ratio and arithmetic is common difference i am just confused