I've tried to answer this, but I just don't seem to get the right equation to begin with. Help, please?

The distance between city A and city B is 280 km. If in going from city A to B, a car traveled 30 kph faster than usual, the trip would've required 3 hours less than the usual time. Find the original speed of the car.

Thank you!!

Question

I've tried to answer this, but I just don't seem to get the right equation to begin with. Help, please?

The distance between city A and city B is 280 km. If in going from city A to B, a car traveled 30 kph faster than usual, the trip would've required 3 hours less than the usual time. Find the original speed of the car.

Thank you!! <3

anonymous · Answer

$$\frac{280}{u}-\frac{280}{u+30}=3$$

anonymous · Answer

Hi! Could you also explain how you came up with the equation? Thank you! :)

anonymous · Answer

distance/speed=time

anonymous · Answer

original speed=$$40 km/h$$

anonymous · Answer

since distance = speed * t so...
Time=d/s
so,(280/x) - (280/x+30)= 3
so, Time - Time = Time   :)

anonymous · Answer

Hi  phoebeco. understood ??  Medel plz  :) :)

anonymous · Answer

distance/original speed=time taken before increasing speed.
distance/increased speed=time taken after increasing speed
subtraction yields 3hrs. as per question.

anonymous · Answer

plz contribute to my medel....  have none :( 
inspire me to help by giving medel

anonymous · Answer

hope u r inspired:)

anonymous · Answer

:) yes...........

anonymous · Answer

thank you guys, so much!! :) well explained!