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OpenStudy (anonymous):
How do you change a temperature that is in Fahrenheit to Celsius form?
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OpenStudy (amistre64):
we can create a function; that has already been created :) by knowing that 0 = 32 and 100= 212
OpenStudy (amistre64):
the slope between then and the points give us a formula to follow
OpenStudy (amistre64):
F,C
----
212,100
- 32, 0
--------
180,100; slope = y,x = 100/180 = 10/18 - 5/9
C-0 = 5/9(F - 32)
C = (5/9)F - 160/32
C = (5/9)F - 5 i believe
OpenStudy (amistre64):
100 = 5/9(212) - 5 should work if i did it right
i think it should be -32 and not -5 tho....
OpenStudy (amistre64):
160/32 is where i missed it ; thats a typo
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OpenStudy (anonymous):
Thanks
OpenStudy (amistre64):
i looked it up and it says:
C = 5/9(F-32) ; i shoulda stopped while I was ahead lol
OpenStudy (amistre64):
at f = 212 that sould be c - 100 then
212
-32
----
180(5)
------ = 100 all right :)
9
OpenStudy (amistre64):
dispite my apparent stupidity; did that make sense?
OpenStudy (anonymous):
yeah actually it did
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OpenStudy (amistre64):
good :) i knew you smart ;)
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