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If \[\tan(\frac \pi 2 \sin a)=\cot(\frac \pi 2 \cos a)\] then cos a +sin a =
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1
i got that too. but the answer is -1
no wait it says.. it could be 1 or -1
do you know how to get -1?
use tanx=tany implies x=n(pi)+y where n is integer.
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u get cosa+sina=2n+1. when n=0 u get 1 and when n=-1 u get -1
which means we can get any no. upto both ways of infinity??
also use the fact that -rt(2)=<cosa+sina<=rt(2) which narrows down n to ONLY 0 and -1
oh...okay..
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