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equation that I need help with is 8 over 3 plus sqrt 7
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\[\frac{8}{3+\sqrt{7}}\]
is that it
well if it is multiply top and bottom by conjugate \[\frac{8}{3+\sqrt{7}}*\frac{3-\sqrt{7}}{3-\sqrt{7}}\] \[=\frac{24-8\sqrt{7}}{2}\] factor out a 2 on top which cancels the 2 on bottom leaving \[= 12-4\sqrt{7}\]
wonderful! how did you come up with the 8, though? is it that you must include the same number you multiply with in the top equation?
and how in the heck did you get 2?
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oh, never mind. thank you!
by distributing on top, FOIL on bottom your welcome :)
quick question- for these types of problems, will the denominator always be 2?
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