(x-4)^2/9-(y+2)^2/16=1

give the exact coordinates of any four points on the hyperbola.

and show me how you get this

Question

(x-4)^2/9-(y+2)^2/16=1

give the exact coordinates of any four points on the hyperbola.

and show me how you get this

anonymous · Answer

wouldn't you just plug in any x or y number and factor to get the corresponding x or y value?

anonymous · Answer

First, try setting x=0, then y=0, these should be the easiest 2 points to get

anonymous · Answer

agreed

toxicsugar22 · Answer

yes but can u help me further i tried

toxicsugar22 · Answer

hi can u help me

anonymous · Answer

do you have a mac?

anonymous · Answer

if so, open grapher and plot the equation, this will let you see the curve.

anonymous · Answer

here is the algebra for x=0

$$16/9 - (y+2)^{2}/16 = 1$$

$$5/9 = (y+2)^{2}/16$$

$$40/9 = (y+2)^{2}$$

$$y = -2+ (\sqrt{40})/3$$

anonymous · Answer

so that coordinate would be $$(0, -2+(\sqrt{40})/ 3)$$