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(x-4)^2/9-(y+2)^2/16=1 give the exact coordinates of any four points on the hyperbola. and show me how you get this
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wouldn't you just plug in any x or y number and factor to get the corresponding x or y value?
First, try setting x=0, then y=0, these should be the easiest 2 points to get
agreed
yes but can u help me further i tried
hi can u help me
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do you have a mac?
if so, open grapher and plot the equation, this will let you see the curve.
here is the algebra for x=0 \[16/9 - (y+2)^{2}/16 = 1\] \[5/9 = (y+2)^{2}/16\] \[40/9 = (y+2)^{2}\] \[y = -2+ (\sqrt{40})/3\]
so that coordinate would be \[(0, -2+(\sqrt{40})/ 3)\]
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