Question

(x-4)^2/9-(y+2)^2/16=1

give the exact coordinates of any four points on the hyperbola.

and show me how you get this

Answer 1

wouldn't you just plug in any x or y number and factor to get the corresponding x or y value?

Answer 2

First, try setting x=0, then y=0, these should be the easiest 2 points to get

Answer 3

agreed

Answer 4

yes but can u help me further i tried

Answer 5

hi can u help me

Answer 6

do you have a mac?

Answer 7

if so, open grapher and plot the equation, this will let you see the curve.

Answer 8

here is the algebra for x=0

\[16/9 - (y+2)^{2}/16 = 1\]

\[5/9 = (y+2)^{2}/16\]

\[40/9 = (y+2)^{2}\]

\[y = -2+ (\sqrt{40})/3\]

Answer 9

so that coordinate would be \[(0, -2+(\sqrt{40})/ 3)\]