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Mathematics 22 Online
OpenStudy (anonymous):

What are the odds against getting a sum of 5 when rolling a pair of dice?

OpenStudy (anonymous):

draw out all the possible case, use complemenaty even

OpenStudy (anonymous):

event

OpenStudy (anonymous):

draw up a table , 6 x 6 and list 1,2,3,4,5,6 on the rows and columns of the table

OpenStudy (anonymous):

6 in 36

OpenStudy (anonymous):

then find all the possible sums

OpenStudy (anonymous):

okk.. 6?

OpenStudy (anonymous):

wrong

OpenStudy (anonymous):

fairly sure its 4/36

OpenStudy (anonymous):

if you draw up a table

OpenStudy (anonymous):

ok! because it cant be 5 by itself, so that eliminates 2 options, so it is 4.

OpenStudy (anonymous):

1+4, 2+3, 3+2, 4+1. 4 sorry, there are no zeros

OpenStudy (anonymous):

draw up a table :|

OpenStudy (anonymous):

i did

OpenStudy (anonymous):

chances of sum of 5 is 4/36 = 1/9 therefore chances of not getting a sum of 5 is 8/9 the complementary event

OpenStudy (anonymous):

thank you!

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