Question

find two complex zeros:
3x^2+4x+14=0
anyone understand?

Answer 1

use the quadratic formula to find out

Answer 2

\[x= -4 \pm \sqrt{4^2-3*4*14}/2*3\]

Answer 3

\[x=-4\pm \sqrt{16-168}/6\]

Answer 4

x=-b±√b^2-4ac/2a ?

Answer 5

right

Answer 6

x= -4 +/-2sqrt(38)i/6

Answer 7

i understand how it works now,
thanks for the reply uzma

Answer 8

thats good, welcome:)