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How do you rewrite this expression using positive exponents only? 3s^1/3 * s^-7/3
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3/x^2
\[3s ^{1/3}\times s ^{-7/3}\]
\[3s ^{1/3}\times s ^{-7/3} = 3 \times s ^{(1/3) + (-7/3)}\] \[3 \times s ^{-6/3}\] \[3 \times s ^{-2}\] since \[s ^{-2} = 1/s^2\] so we have \[3/s^2\]
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