Question

How do you rewrite this expression using positive exponents only? 3s^1/3 * s^-7/3

Answer 1

3/x^2

Answer 2

\[3s ^{1/3}\times s ^{-7/3}\]

Answer 3

\[3s ^{1/3}\times s ^{-7/3} = 3 \times s ^{(1/3) + (-7/3)}\]
\[3 \times s ^{-6/3}\]
\[3 \times s ^{-2}\]
since \[s ^{-2} = 1/s^2\]
so we have \[3/s^2\]