4x+3 * x+3 do i cancel out the 3?
\[(4x+3)(x+3)?\]
order of operations? and foil.
\[4x^2+15x+9\]
Here was the original expression. \[4x+3 \over x-5\] \[\times\]\[x-5 \over x+3\]
how do i go from there?
you can cancel out the (x-5)
thats what i thought , what would i do from there though?
then you would have 4x+3/x+3 not much you can do. what was the question asking you do?
This is what the question says, Use your understanding of multiplying and dividing fractions to rewrite the expressions below. Then look for "ones" and simplify. For each rational expression, also stadte any valuses of the varibles that would make the denomintaior zero. here is the full question... http://hotmath.com/help/bookindexes/cpm06/index.html?myhm=true#pid=cpm06_10_1_Classwork_10-15_412
valuses of the varibles that would make the denomintaior zero would be x= -3
valuse of the variable that would make the denomintaior zero would be x= -3
how did you come to find that?
valuse of the variable that would make the denomintaior zero would be x= -3
what is the simplified version?
this is the simplest 4x+3/x+3 nothing else you can do
\[x \neq -3\] then the whole thing would be Undefined Slope, No Slope
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