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Solve. x=sqr rt x+13+7
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is it \[x=\sqrt{x+13}+7\]?
yes
if so then \[x-7=\sqrt{x+13}\] square both sides
\[x^2-14x+49=x+13\] \[x^2-15x+36=0\]
factor \[(x-13)(x-2)=0\] \[x=13\] \[x=2\]
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now you have to check because step two was squaring.
oops i factored wrong!
oh
\[(x-12)(x-3)=0\] \[x=12\] \[x=3\]
now check and you will see that 12 works and 3 does not
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ok. thats what i got. thanks for confirming. medal
so answer is 12
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