Question

The area of an isosceles trapezoid is 90 in squared, the height is 6 inches, and the congruent legs are 10 inches. Find the length of the longer base.

Answer 1

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

Answer 2

take out the area that they give you and your left with a triangle right?

Answer 3

90 - 60 =30

we have an area of 30 to account for

Answer 4

I dont think im following you. How'd you get 60?

Answer 5

the height is 6 so.......

6b/2 = 30

3b = 30

b = 10 more than the other one

Answer 6

the area of a rectangle is base times height right?

6.10 = 60

Answer 7

90 total - 60 that is given = 30 left

Answer 8

But 10 is the leg not a base. So it would make triangle not a square right?

Answer 9

the longer base = 20

Answer 10

i see it lol

Answer 11

Im confused. What is 90 and how did you know that 10 was the base>>

Answer 12

then we pythag it to find the 'base'

Answer 13

see what?

Answer 14

i see that i read the problem wrong and know how to fix it...

Answer 15

6^2 + b^2 = 10^2

b^2 = 100 - 36

b = sqrt(64) = 8 , roght?

Answer 16

like this; and the problem says the trap area = 90

Answer 17

Hold on im working it out

Answer 18

Right i got that

Answer 19

6*16
----- = 48 for the 'area' of the triangle
2

90 - 48 = 42

6(7) = 42......

small side = 7
large side = 23 then right?

Answer 20

im working it

Answer 21

Wait I think I'm getting it but your saying 48 is the area for both the small triangles right?

Answer 22

yes;

Answer 23

together they make one triangle with a height of 6 and a base of 16

Answer 24

Oh! I got it. THanks for the help