Question

A=1
_h(b+c) for b i really need help with this one
2

Answer 1

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

Answer 2

Hmm. Are you trying to solve for b? And do you have values for A/h/c or do you just want it in terms of A, h, and c?

Answer 3

ok here it is...i got b=2A-c

Answer 4

gfa -- you seem to have missed `h'.

Answer 5

thanks

Answer 6

I am just having a hard time with this class

Answer 7

So the steps are:

\[\begin{align}
A &= \frac{1}{2}h(b + c)\\
2A &= h(b+c)\\
\frac{2A}{h} &= b + c\\
\frac{2A}{h} - c &= b
\end{align}\]

First you multiply both sides by 2 to cancel out the 1/2. Then you divide both sides by h to cancel out the h on the right. Then you subtract c from both sides. Finally, b is alone :)

Answer 8

okay so i did it right then i wasn't sure

Answer 9

i have just having a horrible time with this Algebra class i had a 92 in now i have an 80

Answer 10

You did? Awesome! :) Always feels good to hear someone else confirm it.

Remember to click `Good Answer' next to answers that are helpful to you here on OpenStudy :)

Answer 11

you are right shdow i missed it lol

Answer 12

Feel free to ask any other questions. Hopefully that grade can go back up :) Algebra can be tough, but if you keep pushing it'll make more and more sense.

Answer 13

I appreciate the help i have a test that i am studying for

Answer 14

I need it to go back up i have a 3.5 gpa i can't loose that

Answer 15

All right then, good luck on that test!

Answer 16

sure you don't mind

Answer 17

i just have couple hard ones that i an having a hard time with

Answer 18

Yeah, I'd post them separately on the left, that way people can try to help with each one when they think they can.

Answer 19

okay thanks i will give me a few minutes i dropped my calculator