A=1 _h(b+c) for b i really need help with this one 2
Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!
Hmm. Are you trying to solve for b? And do you have values for A/h/c or do you just want it in terms of A, h, and c?
ok here it is...i got b=2A-c
gfa -- you seem to have missed `h'.
thanks
I am just having a hard time with this class
So the steps are: \[\begin{align} A &= \frac{1}{2}h(b + c)\\ 2A &= h(b+c)\\ \frac{2A}{h} &= b + c\\ \frac{2A}{h} - c &= b \end{align}\] First you multiply both sides by 2 to cancel out the 1/2. Then you divide both sides by h to cancel out the h on the right. Then you subtract c from both sides. Finally, b is alone :)
okay so i did it right then i wasn't sure
i have just having a horrible time with this Algebra class i had a 92 in now i have an 80
You did? Awesome! :) Always feels good to hear someone else confirm it. Remember to click `Good Answer' next to answers that are helpful to you here on OpenStudy :)
you are right shdow i missed it lol
Feel free to ask any other questions. Hopefully that grade can go back up :) Algebra can be tough, but if you keep pushing it'll make more and more sense.
I appreciate the help i have a test that i am studying for
I need it to go back up i have a 3.5 gpa i can't loose that
All right then, good luck on that test!
sure you don't mind
i just have couple hard ones that i an having a hard time with
Yeah, I'd post them separately on the left, that way people can try to help with each one when they think they can.
okay thanks i will give me a few minutes i dropped my calculator
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