find the height of a prism of a base if the volume is 9 and the area of the base is 18
volume of a prism = area of base x height so plug in your 2 values and solve the equation
i assume that the prism is standing on its end!
if the base of a right prism is a rhombus with diagonals 10 in and 12 in and the volume of the prism is 60 cu in find the height of the prism please help!
i really dont understand geometry at alll!
well we usually talk about the length and cross sectional area of a prism. I prism is a 3 dimensional object with a uniform cross section - a bit like a toblerone bar of chocolate
ok . could you please explain to me how to solve the problem
well assume the prism is resting on its base which is a rhombus then its volume = area of the rhombus x the height so 60 = area of rhombus x h so we need to calculate the area of the rhombus
hold on a bit - to be honest i'm stuck with that bit
ok so its going to be d1d2 divided by 2 to solve for area
heck! is that the area of a rhombus - you've got that from a maths book or by other means??
other means but when i calulate it it comes out to 60 = 60
i dont remember to be honest
well d1d2 /2 = 30/2 = 15 so qwe have 60 = 15 x h h = 4 height is 4
where did u get 15 from?
where did you get 30 from im lost
sorry - i must be tired its 12 x 10 divided by 2 giving 60 - either the d1d2 formula is wrong or volume = 60 is wrong. hold on and i'll check my maths stuff
ok - the volume d1d2/2 is correct so the answer must be h = 1 60 = 60 x h h=1
is that possible?
lol - thats wrong because the diagonals are in inches and the volume is in cubic feet right 60 cu feet = 60 x 12^3 cu ins = 103680 cu ins so 103680 = 60 x h h = 12^3 = 1728 ins or 144 ft
phew - i think thats enough for today my brain is tired
how did you get to that?
well the volume is 60 cu ft isn't it
yes
i 'm going crazy - i've just checked your earlier post - its 60 cu ins there
in which case h = 1 inch as i said earlier
that is possible brit
lol okay thank you but im not done working your brain 2 more questions if you dont mind
give me a medal first! lol
ok so the diagonal of a cube is 7\[\sqrt{3}\] find the voulme of the cube
i assume you mean the diagonal of one side of the cube. by pythagoras (7sqrt3)^2 = 2x^2 (where x = one side of cube) 147 = 2x^2 x = sqrt(147/2) = 8.5732 vlume of cube = (8.5732)^3 = 630.13 correct to 2 dec places
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