Question

the product of two consecutive integers is 110. find the integers?

Answer 1

smart guessing? 10, 11 :D

Answer 2

good guess!

Answer 3

x= is first integer
x+1=next integer
x(x+1)=110

Answer 4

it's been a while myininaya :D. How are you doing?

Answer 5

If you want the method to solve them, assume the numbers x and x+1, then:
\[x(x+1)=110 \implies x^2+x-110=0 \implies (x-10)(x+11)=0\]
So x is either 10 or -11. Hence the numbers are either (10 and 11) or (-11 and -10).

Answer 6

x^2+x-110=0
(x-10)(x+11)=0
i'm fine
x=10 x=-11
if x=10, then x+1=10+1=11 since (11)(10)=110
you could also do
if x=-11, then x+1=-11+1=-10 since (-11)(-10)=110

Answer 7

how are you watchmath guy