Question

please solve by partial diffrentiation (4x^3y^2-ycosxy) w.r.t y

Answer 1

I'll do it part by part...
1. partial differentiate the first part.. x is considered a constant...
8x^3y-(ycosxy)'...

2. the first part is done, now just differentiate the second part, which requires product rule (f'g + fg'). so f = y and g = cosxy and f'=1 and g'=-xsinxy

8x^3y - (cosxy+y(-xsinxy))...

3. clean it up. don't know how much u want it cleaned up though
8x^3y-cosxy+xysinxy

Answer 2

weather girl please solve even this...(y/(x-y)^2)-1/\[\sqrt{(1-x^2)}\]

Answer 3

w.r.t ..y