Mathematics
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OpenStudy (anonymous):
sin 0=
cos 0=
tan 0=
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OpenStudy (anonymous):
OpenStudy (angela210793):
sin0=0
cos0=1
tan0=0/1=0
OpenStudy (anonymous):
about cos 1/?
OpenStudy (angela210793):
wht abt cos1?
OpenStudy (anonymous):
so it is 1/0 or not because i have to find the ration of this problem
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OpenStudy (anonymous):
You are saying sin 0 but you mean
OpenStudy (anonymous):
you mean sin theta?
OpenStudy (anonymous):
yea i support to be 0 with cross but oh well and what sin theta..
OpenStudy (anonymous):
What is your question, when you ask more than one question in same post it becomes confusing. What is your question now?
OpenStudy (anonymous):
when i saw the picture of this problem which i don't know what to do with this..
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OpenStudy (anonymous):
The (6,8) is the lengths. 6 is adjacent, 8 is opposite. From those two use pythagorean theorem to find the hypothenuse.
OpenStudy (anonymous):
oh and i need the ratio of this
OpenStudy (anonymous):
First find the hypotenuse, so that you have all the lengths of the triangles. You remember how to find that?
OpenStudy (anonymous):
like
OpenStudy (anonymous):
a2+b2=c2 right
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OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
with 6 and 10
OpenStudy (anonymous):
6 and 8. Draw the triangle on a piece of paper and fill it out. The x leg or adjacent is 6, the y leg or opposite is 8.
OpenStudy (anonymous):
6sq+xsq=8sq
OpenStudy (anonymous):
6^2+8^2=hypotenuse^2
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OpenStudy (anonymous):
i got 10
OpenStudy (anonymous):
So draw your triangle and you have all the info to find sin, cos, etc
OpenStudy (anonymous):
Sorry
OpenStudy (anonymous):
sorry for...
OpenStudy (anonymous):
repeated posts
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OpenStudy (anonymous):
that a ok