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y=e^sinx
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mmh, and what if I told you \(y=e^{\cos x}\) ?
do you need to solve for x? graph this?
if you are asking for the derivative of the expression, like you were in the last question you asked, then: d/dx e^u = e^u * du/dx, so: derivative of e^sinx = (e^sinx )*cosx
yaaa
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