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Mathematics 18 Online
OpenStudy (anonymous):

y=e^sinx

OpenStudy (nowhereman):

mmh, and what if I told you \(y=e^{\cos x}\) ?

OpenStudy (dumbcow):

do you need to solve for x? graph this?

OpenStudy (anonymous):

if you are asking for the derivative of the expression, like you were in the last question you asked, then: d/dx e^u = e^u * du/dx, so: derivative of e^sinx = (e^sinx )*cosx

OpenStudy (anonymous):

yaaa

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