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Mathematics 9 Online
OpenStudy (anonymous):

I need geometry help and more specifically I need help with question 12 and 13. http://i79.photobucket.com/albums/j123/MistyBlue2010/05-24-2011031019PM.jpg

OpenStudy (anonymous):

Do I just assume that 9 is the total length so x would be half of 9?

OpenStudy (anonymous):

I cant get on photobucket on my computer:/ Could you import it here?

OpenStudy (anonymous):

OpenStudy (anonymous):

lol, just did this sheet:D

OpenStudy (anonymous):

yea? lol

OpenStudy (anonymous):

nice

OpenStudy (anonymous):

kay what exactly do you need help on?

OpenStudy (anonymous):

12 and 13 finding x and y. For x do I just assume that it is half of 9?

OpenStudy (anonymous):

and I have no idea how to find y

OpenStudy (anonymous):

Ok, x is 1/2 of 9 because it is the same distance from the center as the chord with the length of 9. Each chord is perpendicular.

OpenStudy (anonymous):

Then you use Pythagorean theorum to find the radius which is y.

OpenStudy (anonymous):

It is difficult to read but here we go. The two drawn chords are equal in length so both are 9. Therefore x= 4.5 Q13 y is a radius which can be found from the previous answer using Pythagoras again. r squared = 5 squared + 4.5 squared...you can do the rest I think :)

OpenStudy (anonymous):

thanks :)

OpenStudy (anonymous):

My pleasure!

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