Question

Solve: 4x^2+10x=-1
I'd like somebody to walk me through the steps.

Answer 1

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Answer 2

add 1 to both sides
4x^2+10+1=0
Do you know the quadratic formula?

Answer 3

or just transpose -1 one to the left then get the opposite sign

Answer 4

bro you got like 4x^2 +10 - 1 = 0
you cant factor so you gotta quadratic forumal that
-b (plus or minus) Root(b^2-4AC) all divided by 2A

Answer 5

that is supposed to be a plus 1 not a minus

Answer 6

The equation becomes:

4x^2+10x+1=0

You need to use the quadratic formula which is:

x=[-b+/-square root(b^2-4ac)]/2a

a=4
b=10
c=1

x=[-10+/-square root(10^2-4(4)(1)]/2(4)
x=[-10+/-square root(100-16)]/8
x=[-10+/-square root(84)]/8
x=[-10+/-square root(4)*(21)]/8
x=[-10+/-2(square root 21)/8
You can reduce 10, 2 and 8 since each is divisible by 2 and you get:

x=[-5+/-(square root 21)]/4=(-5+square root 21)/4 and (-5-square root 21)/4