Find the derivative of the function f(x) = 3 sqrt x + 2e^x
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ok thanks
f(x)=3x^(1/2)+2e^x f'(x)=3*1/2*x^(1/2-1)+2e^x =3/2*x^(-1/2)+2e^x
what happens the to the 2e^x
(e^x)'=e^x
the derivative is itself
i dont get it
thats just the rules?
e^x is an increasing function (e^x)' is going to be above the x-axis (but e^x is never negative anyways) so can you see how (e^x)'=e^x possibly now?
yes thank you
and yes they did make it a rule but it can be proven
do you have to ask a certain amount of questions to give a person a good answer because am not able to see it the lady said it was suppose to be in the right hand corner
myininaya can you help on the problem i posted please?
its trignometric substitution
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