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Mathematics 11 Online
OpenStudy (anonymous):

nCk= The combinations of n taken k at a time. which of the following is equal to 11C8? a) 11!/3! b) 11!/11!8! c) 11!/8!3! d) 11!/8!

OpenStudy (anonymous):

Is it a..?

OpenStudy (anonymous):

no c

OpenStudy (anonymous):

nCr = n!/r!(n-r)!

OpenStudy (anonymous):

c is the right choice

OpenStudy (anonymous):

nPk = n!/(n-k)1

OpenStudy (anonymous):

right

OpenStudy (anonymous):

dont be confused between permutations and combination , both are different

OpenStudy (anonymous):

yep agreed :D

OpenStudy (anonymous):

I'm confused between the two formulas and two answers

OpenStudy (anonymous):

11C8= 11! ----- 8!*3!

OpenStudy (anonymous):

i have a way combination : we only select the items permutation: we select and we also arrange the items

OpenStudy (anonymous):

umm .. sorry that will be when u do problems of probability

OpenStudy (anonymous):

but metarock ur definition is right

OpenStudy (anonymous):

ya but chizzle was confused in the formulas , a different context though

OpenStudy (anonymous):

Ah, just found a way to remember (P)ermutation ... (P)osition matters both begin with P

OpenStudy (anonymous):

(C)ombination and (C)ounting (or selecting) ;-)

OpenStudy (anonymous):

So then it is 11!/8!3! ?

OpenStudy (anonymous):

yups

OpenStudy (anonymous):

Okay thank you all for the help/formulas/and differences between them

OpenStudy (anonymous):

ur welcome

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