Mathematics
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OpenStudy (anonymous):
how many 3 digit #s can you make with 3-9 if the resulting number has to be divisible by 3?
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OpenStudy (anonymous):
easy
OpenStudy (anonymous):
I guess they are assuming no repeated digits
OpenStudy (anonymous):
yeah since that's just 3* whatever
OpenStudy (anonymous):
so the last position be either 3,6,9 ( so we have 3ways )
3 x 7 x 6
OpenStudy (anonymous):
3-9 = 3,4,5,6,7,8,9 = 7 digits
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OpenStudy (anonymous):
i think it's from 309 to 399, all is divisible by 3
so it's 10
OpenStudy (anonymous):
ergh no, 319 isnt divisivle by 3
OpenStudy (anonymous):
wait I wrotw is wrong
OpenStudy (anonymous):
neither 49
OpenStudy (anonymous):
309, 339,369,and 399.
the answer is 4
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OpenStudy (anonymous):
sum of the digits must be divisible by 3
OpenStudy (anonymous):
yeah
OpenStudy (anonymous):
yeh, if I new that then it would be easier ^
OpenStudy (anonymous):
so how would you proceed with the problem knowing its the sum of the digits that makes it divisible by 3
OpenStudy (anonymous):
r u consider all the numbers between 3 and 9?
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OpenStudy (anonymous):
yeah 3 4 5 6 7 8 9
OpenStudy (anonymous):
oh if so, then my answer is wrong, sorry i misunderstood the question
OpenStudy (anonymous):
haha that's ok
OpenStudy (anonymous):
is it between 3 and 9 or from 3 to 9?
OpenStudy (anonymous):
from 3 to 9 so 3 and 9 inclusive
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OpenStudy (anonymous):
the last digit wuold be 12 becacause 12 divided by 3 would bring 4
OpenStudy (anonymous):
1 and 2 are not included
OpenStudy (anonymous):
nope 1 and 2 aren't included
or 0 either