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Mathematics 19 Online
OpenStudy (anonymous):

how many 3 digit #s can you make with 3-9 if the resulting number has to be divisible by 3?

OpenStudy (anonymous):

easy

OpenStudy (anonymous):

I guess they are assuming no repeated digits

OpenStudy (anonymous):

yeah since that's just 3* whatever

OpenStudy (anonymous):

so the last position be either 3,6,9 ( so we have 3ways ) 3 x 7 x 6

OpenStudy (anonymous):

3-9 = 3,4,5,6,7,8,9 = 7 digits

OpenStudy (anonymous):

i think it's from 309 to 399, all is divisible by 3 so it's 10

OpenStudy (anonymous):

ergh no, 319 isnt divisivle by 3

OpenStudy (anonymous):

wait I wrotw is wrong

OpenStudy (anonymous):

neither 49

OpenStudy (anonymous):

309, 339,369,and 399. the answer is 4

OpenStudy (anonymous):

sum of the digits must be divisible by 3

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

yeh, if I new that then it would be easier ^

OpenStudy (anonymous):

so how would you proceed with the problem knowing its the sum of the digits that makes it divisible by 3

OpenStudy (anonymous):

r u consider all the numbers between 3 and 9?

OpenStudy (anonymous):

yeah 3 4 5 6 7 8 9

OpenStudy (anonymous):

oh if so, then my answer is wrong, sorry i misunderstood the question

OpenStudy (anonymous):

haha that's ok

OpenStudy (anonymous):

is it between 3 and 9 or from 3 to 9?

OpenStudy (anonymous):

from 3 to 9 so 3 and 9 inclusive

OpenStudy (anonymous):

the last digit wuold be 12 becacause 12 divided by 3 would bring 4

OpenStudy (anonymous):

1 and 2 are not included

OpenStudy (anonymous):

nope 1 and 2 aren't included or 0 either

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