Question

what are the intercepts of the equation
2x+3/2y+3z=6

Answer 1

is it (3,0,0) (0,4,0)(0,0,2)

Answer 2

2x+3
------ -= 6 ; is this the equation?
2y+3z

Answer 3

no its a fraction

Answer 4

2x +3/2y +3z = 6 this then :)

Answer 5

yes its a graphing equation

Answer 6

we need to multiply everything by y; to get rid of that bit

Answer 7

its gong to be 4

Answer 8

2xy +3/2 +3zy = 6y is the sane equation, but has no limits when y = 0

Answer 9

2xy +3/2 +3zy -6y = 0

y(2x +3z -6) +3/2 = 0 is another way of writing it

Answer 10

when x and y = 0 there is no value..... is there?

Answer 11

this is the answer i been got it (3,0,0) (0,4,0)(0,0,2)

Answer 12

is that answer correct? or is that the answer you are checking?

becasue y cant = 0 in this..

Answer 13

(0,4,0) is good

(x,0,0) is not valid, becasue y cant be 0

(0,0,z) is not valid cause y cant = 0

Answer 14

in other words, yo have a function that only intersects the y axis; and never touches the other 2

Answer 15

no, he means its a plane

Answer 16

not a fraction

Answer 17

people need to get the notation correct when asking a question , the fracts are coeffiecients of the plane

Answer 18

the surface is a hyperbolic cylindar

Answer 19

hello amistre!

Answer 20

oh lol

Answer 21

hi sat :)

Answer 22

did you take yesterday off?

Answer 23

i wish lol.... I spent the day under my front end fixing the steering parts...

Answer 24

i meant from "off from here"

Answer 25

and to the asker, yes the answers you posted in the first post are correct

Answer 26

it was a forced hiatus lol

Answer 27

oh yes. it is right. set two = 0 solve for third

Answer 28

2x+(3/2)y+3z=6

4x +3y +6z = 12

x=3, y=4, z=2

(3,0,0) (0,4,0) (0,0,2) would then be the intercepts yes