simplify (-32a^10)^(3/5)
First, it's important to recognize that 32 and \(a^{10}\) are 5th powers. So, taking fifth roots, we get \((-2a^{2})^{3}\). Are you good from here?
no. what do you mean 5th roots??
So 5th roots are kind of like square roots
4 is the square of 2, so \(\sqrt{4}=2\).
\(2^{5}=32\), so \(32^{1/5}=2\).
ok and you get a^2 by dividing 10 by 5 right?...so what happened to the denominator of five outside the ()?
That goes away because we divided the powers by 5.
...ok so is that the final answer?
Well no, now you still have to cube it.
-8a^6 correct?
Perfect.
ok cool so how would you do (9^(1/2)+16^(1/2))^-2?
Ick, that's an ugly one. Are you sure there is a plus in there?
haha ya
Stupid me, it's way easy, 9 and 16 are squares.
oh ok i see it :P do you know what 7^-2 would be?
\[\frac{1}{7^{2}}\], right?, which then becomes? (leave it in a fraction)
oh ok! if you dont mind could you help me with like four more? i have this as a precalc summer assignment and we havent learned any of this yet.
Actually, I can't sorry, I have to take off. I am tutoring someone at 5.
ok well thanks for the help!
You're very welcome, sorry I couldn't help you on the other four.
its fine.
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