Mathematics
10 Online
OpenStudy (anonymous):
if ln5=a and ln3=b write ln0.12 as an expression in a and b
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OpenStudy (anonymous):
.12=2*3/2*5
OpenStudy (sgadi):
0.12=12/10=6/5=2*3/5
ln(2*3/5)=ln2+ln3-ln5=ln2+b-a
OpenStudy (anonymous):
sorry that is wrong.
\[.12=\frac{2\times 3}{(2\times 5)^2}\]
OpenStudy (anonymous):
actually .12=12/100 but that is the right idea
OpenStudy (anonymous):
i mean sgadi has the right method
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OpenStudy (anonymous):
so ln2+b-a is the answerÉ
OpenStudy (anonymous):
not what i get
OpenStudy (anonymous):
what you get im lost
OpenStudy (anonymous):
ok lets go slow
OpenStudy (anonymous):
\[.12=\frac{12}{100}\]
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OpenStudy (anonymous):
now reduce this to
\[\frac{12}{100}=\frac{3}{25}\]
OpenStudy (anonymous):
now it is easy
OpenStudy (anonymous):
ish
OpenStudy (anonymous):
but where does a and b come in
OpenStudy (anonymous):
\[ln(\frac{3}{25})=ln(\frac{3}{5^2})\]
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OpenStudy (anonymous):
not there yet is is coming
OpenStudy (anonymous):
\[ln(\frac{3}{5^2})=ln(3)-ln(5^2)\]
OpenStudy (anonymous):
=\[ln(3)-2ln(5)\]
myininaya (myininaya):
ln(12/100)=ln(3/25)=ln3-ln5^2=ln3-2ln5=b-2a
OpenStudy (anonymous):
and there is your a and b.
\[ln(3)-2ln(5)=a-2b\]
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OpenStudy (anonymous):
the gimmick was to rewrite these in terms of ln(3) and ln(5)
myininaya (myininaya):
b=ln3
a=ln5
so its b-2a
OpenStudy (anonymous):
thanks you!