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f(x)=x^2+4x+1, identify the vertex and axis of symmetry.
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complete the square to get \[f(x)=(x+2)^2+1-4=(x+2)^2-3\]
vertex is (-2,-3) and axis of symmetry is x=-2
or you could just use \[-\frac{b}{2a}=-\frac{4}{2}=-2\] and \[f(-2)=(-2)^2+4\times -2+1=4-8+1=-3\]
thanks A LOT
\[-\frac{b}{2a}\] is usually easier because you do not have to keep track of adding and subtracting. to find the y coordinate just substitute
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