Question

31+49 cos(theta)=49 sin^2(Theta)

Answer 1

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Answer 2

..... /49

31/49 + cos(t) = sin^2(t) for a start?

Answer 3

sin^2(t) = sqrt(1 - cos^2(t)) sooo....

31/49 + cos(t) = sqrt(1 - cos^2(t))

Answer 4

(31/49)^2 + cos^2(t) + (62/49)cos(t) = 1 - cos^2(t)

Answer 5

2cos^2(t) + (62/49)cos(t) +1 + (31/49)^2 = 0

Answer 6

u = cos(t)

2u^2 + (62/49)u +(1 + (31/49)^2) = 0

Answer 7

where did the 32/49 come from lol, there wasnt even a fraction to misinterperate!

Answer 8

divide it all by 49 in the begining

Answer 9

2u^2 + (62/49)u +(-1 + (31/49)^2) = 0 typoed lol