Ask your own question, for FREE!
Mathematics 12 Online
OpenStudy (anonymous):

Find three consecutive even integers such that the sum of the first two is greater than 27 and the sum of the last two is less than 39

OpenStudy (anonymous):

14,16,18

OpenStudy (anonymous):

three consecutive integers can be written 2n, 2n+2, 2n+4 where n is an integer. 2n+2n+2>27 4n>25 2n+2+2n+4<39 4n<33 so to satisfy both we can use n=7 then the integers are 14,16,18

OpenStudy (anonymous):

consecutive *even integers

OpenStudy (anonymous):

OR 16,18,20

OpenStudy (anonymous):

yep n=8 works too

OpenStudy (anonymous):

14,16,18 OR 16,18,20

OpenStudy (anonymous):

n + n+1 > 27 N+1 +n + 2 < 39 2n + 1 > 27 2n + 3 < 39 2n > 26 2n < 39 n > 13 n < 19.5 14 16 18

OpenStudy (anonymous):

no its 2n > 26 and 2n < 36 of course

OpenStudy (anonymous):

n > 13 and n < 18 14 16 18 and 16 18 20 are correct

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!