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Evaluate the limit of (x^2+3x)/(abs(x)-3) as x approaches -3
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wht's absx?
absolute, i guess
ok thnx :)
yea it is absolute i promise
yeah absolute value of x
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so indeterminate form
sexy mama thanx for become my fans :D
right.
ur welcome suzi20
(x^2+3x)/(x-3) where x\[\ge\] 0
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the form is o/o so do l'hospital
and (x^2+3x)/(-1)(x-3) where x\[<\]0
No that is wrong. For \(x<0\) you get \((x^2+3x)/(-x-3)\)
yeah sorry, I meant (-1)(x+3)
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