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Mathematics 8 Online
OpenStudy (anonymous):

Evaluate the limit of (x^2+3x)/(abs(x)-3) as x approaches -3

OpenStudy (angela210793):

wht's absx?

OpenStudy (anonymous):

absolute, i guess

OpenStudy (angela210793):

ok thnx :)

OpenStudy (anonymous):

yea it is absolute i promise

OpenStudy (anonymous):

yeah absolute value of x

OpenStudy (anonymous):

so indeterminate form

OpenStudy (anonymous):

sexy mama thanx for become my fans :D

OpenStudy (anonymous):

right.

OpenStudy (anonymous):

ur welcome suzi20

OpenStudy (anonymous):

(x^2+3x)/(x-3) where x\[\ge\] 0

OpenStudy (anonymous):

the form is o/o so do l'hospital

OpenStudy (anonymous):

and (x^2+3x)/(-1)(x-3) where x\[<\]0

OpenStudy (nowhereman):

No that is wrong. For \(x<0\) you get \((x^2+3x)/(-x-3)\)

OpenStudy (anonymous):

yeah sorry, I meant (-1)(x+3)

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