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Mathematics 16 Online
OpenStudy (anonymous):

How do you determine if a polynomial is the difference of two squares?

OpenStudy (anonymous):

waits for amistre

OpenStudy (amistre64):

im here lol

OpenStudy (anonymous):

a suggestion is try to factor

OpenStudy (amistre64):

it got the '-' in it

OpenStudy (amistre64):

thats a big clue

OpenStudy (anonymous):

yeah big clue

OpenStudy (amistre64):

and if you see that the sides can be sqrted thats another

OpenStudy (amistre64):

usually; if it has a square in it and has a - they want you to diff it

OpenStudy (anonymous):

I don't think you can have a odd exponent as the leading term

OpenStudy (amistre64):

you can; but it all depends on how anal a program is lol

OpenStudy (anonymous):

oh

OpenStudy (amistre64):

you said exponent.... i read coeeff

OpenStudy (amistre64):

..... still may apply tho lol

OpenStudy (anonymous):

happens to me all the time. im fukin dyslexic or something

OpenStudy (anonymous):

how did her question get from facotring to such an analytical question. Interesting text book

OpenStudy (amistre64):

\(x^{\sqrt{5}}\)

OpenStudy (anonymous):

or maybe th answer is in the introductioin of the cchapter

OpenStudy (amistre64):

\[x^{5^{1/2}}\] lol

OpenStudy (anonymous):

x^ 1/5 - 0 X^1/5+ 0 ?

OpenStudy (anonymous):

I just need a 50 word response for my paper that is all I need

OpenStudy (anonymous):

is this a grad course on teaching algebra?

OpenStudy (anonymous):

So I am trying to put that all down and in the correct form so that it sounds right

OpenStudy (anonymous):

I don't know the definate answer to your question

OpenStudy (anonymous):

No it is my algebra/117 my last basic class that I need

OpenStudy (amistre64):

uhoh..... if you qoute me youre gonna need alot of ****

OpenStudy (anonymous):

Praphrase

OpenStudy (amistre64):

amistre64 says yada yada yada; someday it may even be proven correct lol

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

I am trying to write on my own I just need something to get started with

OpenStudy (anonymous):

write P=NP

OpenStudy (anonymous):

i'll give you $400,000 if you can prove that

OpenStudy (anonymous):

I think im short changing you, too

OpenStudy (amistre64):

P=NP when P=0

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

that's not proving P=NP, that's a case

OpenStudy (amistre64):

;)

OpenStudy (anonymous):

you can use a case to prove but you can't prove by cases

OpenStudy (amistre64):

\[x^y + y^x = xy^{x+y}\]

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