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find the second derivative of the function: f(x) = (x^3-2x)^4
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my real problem is what the 4th power and expanding the brackets i know how to find th derivative
f'=4(x^3-2x)^3 * (3x^2-2) expanding the brackets?
wouldn't do that. use product rule make you life easier
f''=4*3(x^3-2x)^2*(3x^2-2)*(3x^2-2)+4*(6x)(x^3-2x)
ooops that last parthesis i left out a third power
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myininaya you are a calculating machine!
i wish you are the best not me :(
i dont understand how u expanded that myininaya
what happened to expanding using pascals triangle>?
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