Question

how do you solve 4+5e^-x=0

Answer 1

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

Answer 2

Rearrange and take logarithm on both sides! :)

Answer 3

i still don understand

Answer 4

Subtracting 4 from both sides gives \(5e^{-x}=-4\). Now divide both sides by 5, you get \(e^{-x}=- \frac{4}{5}\). But the exponent function has only positive values in \( \ R \). So, the equation has no real solutions.

Answer 5

exponential function*

Answer 6

u understood amberllg?