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help plz solve:- (log X)^2 + log X^2 = (log2)^2 -1
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\[(\log X)^{2} + \log X ^{2} =(\log 2)^{2} -1\]
what kind of problem is this
solve find x = ?
linear equation?
yes
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not sure can u find a calculator on google to do it?
it so easy
u got it already?
I can't
you put its sooo easy
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my bad
can you solve IT ?
what is it?
Using properties of logs rewrite it like this (log X)^2 + 2log X = (log2)^2 -1 Take the 1 to the other side (log X)^2 + 2log X +1 = (log2)^2 Notice the quadratic on the left (log(X)+1)^2=(log2)^2 Can you go from there?
ok
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