Question

solve x^2+6x-4=0

Answer 1

use the quadratic formula here

Answer 2

here a=1, b=6, c= -4
x= [-b + sqrt(b^2 - 4 ac)]/2a

Answer 3

just pkug in those numbers

Answer 4

easier here to complete the square since the middle term is +x\[x^2+6x=4\]
\[(x+3)^3=4+9=13\]
\[x+3=\pm\sqrt{13}\]
\[x=-3\pm\sqrt{13}\]

Answer 5

quadratic formula forces a denominator on you and then it is a pain to simplify

Answer 6

x=[-6 + sqrt(6^2 -4(1)(-4))]/2(1)
x=[ -6 + sqrt(36 + 16)]/2
x=[-6 + sqrt(52)]/2
x=[-6 + 2sqrt(13)]/2
x=[-3 + sqrt 13] and
x= -3 - sqrt 13

Answer 7

i think its also good for the beginers to learn to use the quadratic formula...lol

Answer 8

it will be very much faster and fun to do it in calculator...lol

Answer 9

i won't argue but i used 3 steps all dealing with whole numbers. of course the answers are the same, but writing is simplest radical form (correctly) and then factoring and canceling (correctly) is often a can of worms

Answer 10

lol.....