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what is the derivative of f(x)= 3x^2+3 at x=2?
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12
d/dx of (3(x^2)+3) = 6x so at x=2, derivative 6*2=12
y=3x^2+3 dy/dx= 3 d/dx x^2+ d/dx 3 dy/dx = 3(2x)+0 dy/dx = 6x at x=2 6*2=12
yeah 12 is correct like shristi1 showed
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thanks ! : )
12 as dy/dx gives 6x which then produces 12
y=3x^2+3 dy/dx= d/dx(3x^2+3) dy/dx = 3(2x)+0 dy/dx = 6x at x=2 6(2)=12 Answer = 12
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