Question

find the area of a rhombus wiht a perimeter of 40 and an angle of 60

Answer 1

area=(side length)^2 sin theta

Answer 2

A=10^2 sin 60=50sqrt{3}

Answer 3

Perimeter is 40, so side is 40/4=10

You know the height, 10sin(60)=5sqrt(3)

Thus you can find the area!

Answer 4

amogh..there is the square of the side length...no?

Answer 5

Its basically side * sine of side.

Answer 6

Which seems to be a square.

Answer 7

its side^2 sin (angle)

Answer 8

I wrote the same,
Its side* height
=side*side*sine of the side

Answer 9

then it should be 50sqrt(3)

Answer 10

sine of angle, iguess :S

Answer 11

then how do i find the area

Answer 12

uzma gave the answer to that,

Answer 13

i posted it earlier

Answer 14

Softball go to your previous question

Answer 15

A trig solution:
\[100\text{ Sin}\left[\frac{60}{180}\pi \right]=86.6025\]

Answer 16

uzma got it first.