Question

how do u find the exact value of the expression: tan inverse[tan(-pi/4)]?

Answer 1

arctan(tan(x))=x

You're undoing what tan does to x.

So here it would be -Pi/4

Answer 2

not...
tan−1(tanx)=x
only for x (−π/2,π/2)

Answer 3

I'm just asking

Answer 4

i thought its -pi/2
please explain

Answer 5

tan(x)=y/x
tan(-Pi/4)=-1/1=-1
arctan(x) means tangent of what angle gives x?
arctan(-1)=-Pi/4, or also 3Pi/4 is a solution

Answer 6

shouldve said tan(theta)=y/x