The given equation is either linear or equivalent to a linear equation. Solve the equation. u/(u-(u+1)/2)=4
\[\frac{u}{\frac{u-(u+1)}{2}}=4\]?
looks like you have two fraction bars there.
yes satellite. haha
\[\frac{u}{u-\frac{(u+1)}{2}}=4\]
ok well first of all \[u-(u+1)=u-u-1=-1\]
so what you really have is \[\frac{u}{\frac{-1}{2}}=4\]
dividing by one half same as multiplying by 2 so you get \[-2u=4\]
divide by -2 to get \[u=\frac{4}{-2}=-2\]
no. stop. sorry. wait a sec
lol
i stop
myininya has the correct problem shown
:)
well then my answer was the answer to a different question!
;(
using this site as a reference: http://www.wolframalpha.com/input/?i=u%2F%28u-%28u%2B1%29%2F2%29%3D4
any input is appreciated. i'm trying to figure out how to work it...
well that certainly is not a linear equation!
i would combine the fractions on bottom first
The given equation is either linear or equivalent to a linear equation. Solve the equation. u/(u-(u+1)/2)=4
no chance. it is not linear
haha. that's how it's listed in my book :D
well it isn't look at the graph!
are you sure you typed it in correctly?
u = 2
yes. look at the link. that's exactly as it appears in my book :)
sure it isn't -2?
it's 2
aaaaaaaaaaaaaaaaaahhhhhhhhhhhhhhhhhhhhhhh
i see. simplify the compound fraction and you will get 2 lickety split
\[\frac{u}{\frac{2u-(u+1)}{2}}=u \div \frac{(2u-(u+1))}{2}=u \times \frac{2}{u-1}=\frac{2u}{u-1}\]
i don't see... :(
thats the left hand side
\[\frac{2u}{u-1}=4\]
where did you get 2u from?
in the very first step...
ok multiply top and bottom by 2 get \[\frac{2u}{2u-(u+1)}\]
no pellet... lol. okay. i'm with you
clears the annoying 2 in the bottom of the denominator
now as we say in the math biz combine liked terms to get \[\frac{2u}{u-1}\]
satellite cheated and did it the easy way
yeah. he thinks i know things and understand. :p
lol
so we have \[\frac{2u}{u-1}=4\] \[2u=4(u-1)\] \[2u=4u-4\] \[u = 2\] whew
waddya mean cheated? how else do you clear fractions?
wow. EASY!!! why was i stressing that?
lol i was kidding satellite
because it is math
i was taught to multiply the whole left side by the complex fraction u-(u+1/2) and do the same on the right...
math is the best because it is logic english makes no sense
haha. taking math and english.... smh...
ooohhhh i see you subtracted in the denominator then inverted and multiplied. ok that works too.
if you are into long algebra. already annoyed that you can out-latex me! lol
gonna grab some food. will be back to annoy you guys in a little ;) thank you both a lot!
now you are going to out algebra me too. not fair
lol no shorter ways are better than longer ways lol i can only out latex you when you are drunk
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