Question

Find the missing value such that the given binomial is a factor of the given polynomial.

x^2-4x-?, X+6


please show the work

Answer 1

yes you want \[x^2-4x+?=(x+6)(something)\]

Answer 2

when you substitute x = -6 you will have to get 0 as an answer because the first term will be 0. so substitute x = -6 on the left hand side, set = 0 and solve

Answer 3

ahhh i see

Answer 4

\[(-6)^2-4\times (-6)+?=0\]
\[36+24+?=0\]
\[60+?=0\]
\[?=-60\]

Answer 5

so it is
\[x^2-4x-60=(x+6)(x-10)\]

Answer 6

k?

Answer 7

got it thanks!

Answer 8

welcome