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Mathematics 13 Online
OpenStudy (anonymous):

(x+2)(x-3)?

OpenStudy (anonymous):

Foil it out..

OpenStudy (anonymous):

never understood that foil method

OpenStudy (anonymous):

Given two binomials, you have to multiply each term by each term. So lets do it out term by term.

OpenStudy (anonymous):

Well I never did either. Or rather I understand it, but I can't ever be bothered to do it that way.

OpenStudy (anonymous):

Here's what I do instead: \[(x+2)(x-3) = x(x-3) + 2(x-3)\]

OpenStudy (anonymous):

Start with the x+2. You need to multiple out each term in the other binomial(namely x and -3) then add them together. So you get: x(x)+(x)(-3) and (2*x)+(2)(-3)

OpenStudy (anonymous):

then distribute.

OpenStudy (anonymous):

exactly^^

OpenStudy (anonymous):

(x+a)(x+b) = x^2 + (a+b)x + (a*b) substitute a and b

OpenStudy (anonymous):

Works great as long as you're only multiplying two binomials that have only 2 terms each. ;)

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