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square root x+7-x=1
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\(\sqrt{x+7-x}=1\) ? That doesn't make sense because it gives you \(\sqrt{7}=1\). :( Do you mean \(\sqrt{x}+7-x=1\)
Yes teacher. I did mean square root x +7-x=1
actually. its square root x+7
Oh, ok. So it looks like this: \[\sqrt{x+7}-x=1\]?
Yes Sir
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add both sides x and take square of both sides \[x+7=1+2x+x^2\] \[x^2+x-6=0\] \[(x+3)(x-2)=0\] \[x_1=-3, x_2=2\]
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