Question

ln(x^2-3x-1)-ln(x+4)=0 solve for x

Answer 1

ln[(x^2-3x-1)/(x+3)]=0
(x^2-3x-1)/(x+3)=1

Answer 2

that 3 should be a four lol down below

Answer 3

x^2-3x-1=x+4
x^2-4x-5=0
(x-5)(x+1)=0
x=5,-1

Answer 4

lol k

Answer 5

how did you get one on the other side of the equal sign?

Answer 6

ln(x^2-3x-1)=ln(x+4)
hence i got...

Answer 7

e^blah=e^blah
but if the blah is 0
then e^0=1

Answer 8

is that too blah for you?

Answer 9

ohhh ok

Answer 10

I got it. :) thanks

Answer 11

cool!