Question

How would you simplify this rational expression 3x-12 over x-4

Answer 1

3x-12=3(x-4)
so all that would be=3

Answer 2

3x-12 = 3(x-4)
So cancelling out x-4 from numerator and denominator u get 3 as answer

Answer 3

Firstly I would factorise 3x - 12 which is 3(x-4)
Then I would cancel out the (x-4) in the numerator and denominator leaving an answer..
3

Answer 4

Thanks Ange

Answer 5

thanks btw i love that you are giving me the answer but i would like it explained like the one gianfranco did thanks by the way you are all amazing

Answer 6

right...hmmm....sorry :):):) Will do that next time :)

Answer 7

ok -6sx over 4x

Answer 8

-6x/4x?
if this is it then we can simplify x-s ---> -6x/4x=-6/4 then we can simplify with 2---> -3/2

Answer 9

here is the work sheet

Answer 10

u have 2 do all these?/???????? :O:O:O
which r the ones u can't solve?

Answer 11

6-13

Answer 12

ok

Answer 13

7) -6sx/4x?
if this is it then we can simplify x-s ---> -6sx/4x=-6/4 then we can simplify with 2---> -3s/2

Answer 14

so we dont do anything with the s leave it alone

Answer 15

8) 10w^4/15w we can simplify a w---->10W^3/15
and yes we can't do anything with s...:)

Answer 16

so you cancel out a w

Answer 17

I am soo sooo soo sorry...idk wht's wrong with my connection :(:(:( I'm sorry :(
9).....5x-20/(5x+45) we can factorize and simplify a 5---> 5(x-4)/5(X+9)=(x-4)/(x+9)
10)......7x/(-7x+x^2) we can factorize and simplify a x---> 7x/[x*(-7+x)]=x/(-7+x)
11)2x^2/(x^2-2x^3)=we can factorize and simplify a x^2--->2x^2/x^2*(1-2x)=2/(1-2x)
12)....(x+3)/(x^2-3x-18) we can express x^2-3x-18=(x+3)*(x-6) so we can simplify a (x+3) and we'll have =1/(x-6)
13)....(x^2-1)/(1-x)=(x-1)*(x+1)/(1-x)=(x-1)*(x+1)/-(x-1)=-(x+1)
Once again i'm sorry and i really hope u'll understand these :):)