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Mathematics 14 Online
OpenStudy (anonymous):

If you roll a 8.5" x 11" paper into a cylinder, what is the radius?

OpenStudy (owlfred):

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

OpenStudy (anonymous):

first answer: 4.25/(Pi) if rolling it with the 8.5 side down second answer: 5.5/(Pi) if rolling with the 11 inch side down

OpenStudy (anonymous):

how did you get that?

OpenStudy (anonymous):

I agree completely with Rubin!

OpenStudy (anonymous):

Can you explain to me how you got that? I have to show my work.

OpenStudy (anonymous):

sure. the equation for circumference is 2(Pi)R. so since you know the final Circumference (8.5, or 11) you should lay it out like this: 2(Pi)R=(8.5 or 11). then you divide each side by 2, and divide each side by Pi to get (4.25/Pi or 5.5/Pi).. hope that helps

OpenStudy (anonymous):

Ok, that is what I thought. But then I got confused with my answer lol. So when I roll the 8.5" sides making the cylinder's height 8.5", it's radius is 5.5"? And vise versa?

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