Question

square root of 3x-2 + square root of X+3 = 7

Answer 1

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Answer 2

\[\sqrt{3X-2}+\sqrt{X+3 = 7}\]

Answer 3

=7 is not supposed to be under the radical

Answer 4

get one square root by itself
and then square both sides
\[\sqrt{3x-2}=7-\sqrt{x+3}\]
\[3x-2=7^2-2*7*\sqrt{x+3}+(x+3)\]

Answer 5

\[3x-2=49-14\sqrt{x+3}+x+3\]

Answer 6

4x+1=49
4x=48
x=12

Answer 7

\[3x-2-x-3-19=-\sqrt{x+3}\]

Answer 8

\[2x-24=-\sqrt{x+3}\]

Answer 9

uhhh where did you get the 7*2 from in the first message?

Answer 10

(a+b)^2=a^2+2*ab+b^2
(a-b)^2=a^2-2*ab+b^2

Answer 11

now we square both sides again and time we get rid of all the square roots
\[(2x-24)^2=(-\sqrt{x+3})^2\]

Answer 12

ummm...i have no clue what that means...idk where u r pulling the 2 and 7 from to get 14

Answer 13

\[(2x)^2-2*2x*24+24^2=x+3\]

Answer 14

are you sure
you don't know how to multiply (a-b)(a-b)?

Answer 15

ummm maybe...idk what a-b is though...

Answer 16

a minus b?

Answer 17

a number - a different number?
?

Answer 18

ok....but im not sure why that comes up in this equation or what you are subtracting...

Answer 19

we have a-b on the left hand side
i squared it to get rid of the square root
but since i squared that side i squared the other side

Answer 20

i understand that but how did you end up with a 14 before squaring it?

Answer 21

14 after squareing

Answer 22

ok....but what is 14? there's only a 7

Answer 23

(a-b)^2=a^2-2*ab+b^2
a=7
b=sqrt(x+3)
(7-sqrt(x+3))=7^2-2*7(sqrt(x+3))+(sqrt(x+3))^2

Answer 24

that one side i lefted out a square
(7-sqrt(x+3))^2*

Answer 25

there is no -2+7 in the problem though

Answer 26

no there isnt

Answer 27

so then how r u squaring it?

Answer 28

what do you mean?
i'm scaring it
(a-b)^2=a^2-2ab+b^2
do you now understand this part?

Answer 29

squaring* not scaring lol

Answer 30

(a-b)^2=(a-b)(a-b)=a^2-ab-ab+b^2=a^2-2ab+b^2 do you not agree with this?

Answer 31

if i knew what that meant maybe i would...

Answer 32

you kind of need to know how multiply binomials before you can do this type of problem

Answer 33

would you like to practice multiplying binomials?

Answer 34

no! i know how to multiple binomials... i just dont know what you are saying

Answer 35

(a-b)^2=a^2-2ab+b^2
all i did was multiply a-b times a-b
a-b is a binomial
this is multiplying binomials
you don't understand this so it seems you need to practice multiplying binomials

Answer 36

but there are numbers that are not even in the problem

Answer 37

a is 7
b is sqrt(x+3)

Answer 38

=7^2-2*7*sqrt(x+3)+(sqrt(x+3))^2*