Question

Hello can someone help me solve this.
x^2+y^2=74
y-x=2

Answer 1

second equation tells you y = x+2 substitute in first equation to get the answer

Answer 2

\[x^2+(x-2)^2=74\]
\[x^2+x^2-4x+4=74\]
\[2x^2-4x-70=0\]

Answer 3

\[2(x-7)(x+5)=0\]
\[x-7=0\]
\[x=7\]
or \[x+5=0\]
\[x=5\]

Answer 4

oops second should be x = -5

Answer 5

oh damn. it was y - x = 2
so y = x+2

Answer 6

so i was wrong. but doesn't change much except the -4x will be a +4x

Answer 7

\[x^2+(x+2)^2=74\]
\[x^2+x^2+4x+4=74\]
\[2x^2+4x-70=0\]
\[2(x-5)(x+7)=0\]
\[x=5\]
\[x=-7\]

Answer 8

so y = 7 or y = -5
solutions are (5,7) and (-7,5)