Question

a man loses 24% of his money and after spending 75 % of the remainder, he left with Rs133,
how much he had first ?

Answer 1

Let him have y initially
If he loses 24% hes left with 76%
so let x=76y/100 (money left first)
He spends 75% of x, so he has only 25% left
so 25x/100 = 133

Answer 2

so x = 532
y = 100x/76
100 x 532/76

Answer 3

y=700...So he had 700 $ or Rs or whatever

Answer 4

k, thnxx !

Answer 5

you can also think in reverse way. Rs 133 is equal to 25% of what he had after losing.
so 133*4 = 532 is the money he totally had after losing. And Rs 532 is 76%. So initially he had,
\[\left( 532*100 \right)\div76\]
= 700