Question

hey can anyone give me a contradictory proof...

Answer 1

of what?

Answer 2

take that u have to prove if p>=q and p<=q then p=q.
we first take that p=| q .
=| means not equal.
so p=q+k
as p>=q
so q+k>=q
k>=0
similarly as p<=q
so k<=0
both satisfies whern k=0
so p=q+o=>p=q
this contradicts our first assumption..

Answer 3

eg: the proof of 0^0 not= 1 ...

can i get some other proofs like this....

Answer 4

ok..

Answer 5

take 0^0=1
\[\frac{0^a}{0^a}=1\]this violets the basic assumption of mathematics that 0/0 is undefined so 0^0 can't be any finie quantity..