patrick has 15 coins, some dimes and some quarters. if their value is $2.25, how many of each does he have???????

Question

amistre64 · Answer

some amount of dimes + some amount of quarters = 15 coins

d + q = 15  ; means that d = 15-q

some number of d(.10) + some number of q(.25) = $2.25

anonymous · Answer

is it 5q and and 10d

amistre64 · Answer

(15-q)(.10) + q(.25) = 2.25

1.50 -.10q +.25q = 2.25

amistre64 · Answer

.15q = .75

q = .75/.15 = 15/3 = 5

5qs

amistre64 · Answer

which then of course means 10 dimes

anonymous · Answer

Let x and y be the number of dimes and quarters respectively, then $x+y=15$ and $0.1x+0.25y=2.25$. From equation (1) we have $x=15-y$, so $0.1(15-y)+0.25y=2.25 \implies 1.5+0.15y=2.25 \implies y=5$. Therefore $x=10$. So patrick  has 10 dimes and 5 quarters.

anonymous · Answer

so i got it right ty {|: